if the sum of n terms of an ap is 2n square +5n ..find the ap
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Tn=Sn - S(n-1)
=2n2+5n - 2(n-1)^2+5(n-1)
=2n2+5n -2n2-2+4n + 5n -5
=14n-7
so this is general term .....
so AP will be,
7,21,35,.......
=2n2+5n - 2(n-1)^2+5(n-1)
=2n2+5n -2n2-2+4n + 5n -5
=14n-7
so this is general term .....
so AP will be,
7,21,35,.......
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