if the sum of n terms of an ap is 3n square + 5 and its m term is 164 find the value of m
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Answer:m=157
Step-by-step explanation:
s1=3(1)+5=8=a1
s2=3(2)+5=17
a2=s2-a1= 17-8=9
d= a2-a1=9-8=1
am=164
a+(m-1)d=164
8+(m-1)1=164
(m-1)1=156
m-1=156
m=157
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