if the sum of n terms of an ap is 3n2-5 find the third term of this ap
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sum of the n term of an ap is 3n^2-5
sum of the 3 terms of the ap is
3*3^2-5=3*9-5=27-5=22
sum of the 2 terms of the ap is
3*2^2-5=3*4-5=12-5=7
so the 3 rd term is (22-7)=15
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