if the sum of n terms of an ap is given by Sn=n^2-3n find the 2nd term and 10 th term
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Step-by-step explanation:
Sn = n^2-3n
S1 = 1^2-3= 1-3 = -2 =A1
S2 = 2^2-3(2) = 4-6= -2
Now A2 = S2-S1
A2 = -2-(-2) = 0
So A1 = -2 and A2 = 0
so common difference d = 0-(-2)=2
Here second term A2 = 0
and 10th term = A1+9(common difference)
= -2+9(2)
= 16
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