If the sum of n terms of an ap is n^2+4n then 10th term
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3
put n= 1......you get first term = 5
put n= 2.... you get sum of 2 term = 12
from here u can find second term = 12-5= 7
1st term = 5
2nd term = 7
common difference= 2
so 10th term = a+(n-1)d= 5+(10-1)2=23
put n= 2.... you get sum of 2 term = 12
from here u can find second term = 12-5= 7
1st term = 5
2nd term = 7
common difference= 2
so 10th term = a+(n-1)d= 5+(10-1)2=23
Answered by
1
hay the 10 th term is 23
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