Question

if the sum of n terms of an AP is nA+nB² find d where A and B are constants​

Answer 1

Step-by-step explanation:

Sn=nA+nB^2

S1=1xA+1xB^2=A+B^2

S2=2xA+2B^2=2A+2B^2

We know,

t1=S1

Therefore, t1=A+B^2

t2=S2-S1=2A+2B^2-A-B^2=A-B^2

Hence,

d=t2-t1=A-B^2-A-B^2=. -2B^2