If the sum of n terms of an AP is represented by 6n-n^2, then the 10th term is ??
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Answered by
1
Step-by-step explanation:
let n=1
Sn =6n-n^2
S1=6(1)-1^2
=6-1
=5
let n=2
Sn=6n-n^2
S2=6(2)-(2)^2
=12-4
=8
since,a1 =S1
therefore a1 =5
a2=S2-S1
=8-5
=3
d=a2-a1
=3-5
=-2
a10 = a+(n-1)d
=5+(10-1)(-2)
=5+9(-2)
=5-18
=-13
Answered by
2
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