Question

if the sum of n terms of an ap is sn =3n2+5n write its nth term​

Answer 1

Step-by-step explanation:

3n2+5=

3n2+5n

n(3n+5)=

n(3n+5)

Answer 2

Answer:

Sn =

${3n}^{2} + 5n$

therefore

a1 =

${1}^{2} \times 3 + 5 \times 1$

= 8

a2=

$3 \times {2}^{2} + 5 \times 2 - 8$

= 22-8= 14

therefore , d = 14-8 = 6

therefore , n = 8+ (n-1)d

=8+(n-1)6=6n-6+8 = 6n-2

hope it helped you dear...