If the sum of nth terms of an AP is n2+4n then 15 th term will be
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Answer:
15th term is 33
Step-by-step explanation:
Sn = n^2 + 4n
S1 = 1² + 4(1)
= 1 + 4
= 5
S2 = 2² + 4(2)
= 4 + 8
= 12
S1 = a1 = 5
S2 = a1 + a2 = 12
5 + a2 = 12
a2 = 12 - 5
a2 = 7
d = a2 - a1 = 7 - 5 = 2
15th term = a + 14d
= 5 + 14(2)
= 5 + 28
= 33
hope you get your answer
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