Math, asked by njjagan29961, 6 months ago

If the sum of numbers,842 and two other numbers obtained by arranging the digits of 842 in cyclic order is divided by 111, 14 and37 respectively, what will be quotient in each case?

Answers

Answered by vinuevarghese
5

Answer:

The quotients are 14, 111, 42

Step-by-step explanation:

The other two numbers obtained by arranging 842 in cyclic order are 428 and 284

So the three numbers are 842, 428 and 284

Sum of three numbers = 842 + 428 + 284 = 1554

When 1554 is divided by 111

1554/111 = 14

When 1554 is divided by 14

1554/14 = 111

When 1554 is divided by 37

1554/37 = 42

Hence the quotients are 14, 111, 42

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