If the sum of numbers,842 and two other numbers obtained by arranging the digits of 842 in cyclic order is divided by 111, 14 and37 respectively, what will be quotient in each case?
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Answer:
The quotients are 14, 111, 42
Step-by-step explanation:
The other two numbers obtained by arranging 842 in cyclic order are 428 and 284
So the three numbers are 842, 428 and 284
Sum of three numbers = 842 + 428 + 284 = 1554
When 1554 is divided by 111
1554/111 = 14
When 1554 is divided by 14
1554/14 = 111
When 1554 is divided by 37
1554/37 = 42
Hence the quotients are 14, 111, 42
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