Question

if the Sum of
of the
zeroes
of the polynomial ax² - 8u - 4 is 4,then find the value of a?​

Answer 1

a=2

Step-by-step explanation:

Sum of zeroes = 4

$sum \: of \: zeroes \: = \frac{ - b}{a}$

$4 = \frac{ -( - 8)}{a}$

$4a = 8$

$a = \frac{8}{4}$

$a = 2$