Question

if the sum of other first time m terms of an A. P. I is n and sum of the it's first n term is m, I then find sum of first( m+n) term​

Answer 1

Step-by-step explanation:

It is given that the sum of first m terms is same as the sum of its first n terms. Thus, the sum of first (m + n) terms of the AP is zero.

Answer 2

Answer:

Correct option is

A

110

A.P   an   n≥1

First term a1=2

Common difference d=4

Mn= Average of first n terms.

⇒  Mn=nSn=n2n[2a+(n−1)d]

                          =21[2×2+(n−1)4]

                          =2+2(n−1)

⇒  Mn=2+2n−2

⇒  Mn=2n

⇒  n=1∑10Mn=n=1∑10(2n)=22(10)×(11)=110

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