If the sum of p terms of an
a.P is 3p2+4p, find its nth term.
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Answer:
6n+1
Step-by-step explanation:
first term = sum of first 1 term
= 3 + 4 (replace p by 1)
= 7
Sum of first 2 terms =( 3×2²) + (4×2)
= 12 + 8
= 20
so second term = sum of first two terms - first term
= 20 -7
= 13
common difference = second term - first term
= 13 - 7
= 6
so nth term = first term + (n-1) common difference
= 7+(n-1) 6
= 6n + 1
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