Question

If the sum of root is -p and product of root is -1/p then find quadratic polynomial​

Answer 1

Answer:

$p {x}^{2} + {p}^{2} x - 1 = 0$

Step-by-step explanation:

$sum = - p \\ \\ product = \frac{ - 1}{p} \\ \\ \\ {x}^{2} - (sum)x + product = 0 \\ \\ {x}^{2} - ( - p) x+ \frac{ - 1}{p} = 0 \\ \\ {x}^{2} + px - \frac{1}{p} = 0 \\ \\ p {x}^{2} + {p}^{2} x - 1 = 0.$