if the sum of Roots of equation is 2and the sum of cubes are 27
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Hey dear here is ur answer
It is given that a+b=2 and
a³+b³=27
We know that a³+b³=(a+b) ³-3ab
So putting given values and solving
ab=-19/6
We know that formula of equation=x²-(a+b) +ab
Putting values,
We find,
X²-2x-19/6=0
So, 6x²-12x-19=0
Hope it will help you
It is given that a+b=2 and
a³+b³=27
We know that a³+b³=(a+b) ³-3ab
So putting given values and solving
ab=-19/6
We know that formula of equation=x²-(a+b) +ab
Putting values,
We find,
X²-2x-19/6=0
So, 6x²-12x-19=0
Hope it will help you
Titli17012003:
yes
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