If the sum of roots of the equation 3x^1-(3k-2)x-(k-6) = 0 is equal to the product of its roots,
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Sum of the roots is = -(3k-2)/3
Product of the roots is = -(k-6)/3
Given, -(3k-2)/3 = -(k-6)/3
3k-2 = k-6
2k = 8
k = 4.
Product of the roots is = -(k-6)/3
Given, -(3k-2)/3 = -(k-6)/3
3k-2 = k-6
2k = 8
k = 4.
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