Question

if the sum of roots of the quadratic equation is 0 then find value of p x2-(p+4)x+5=0​

Answer 1

Answer:

p=-4

Step-by-step explanation:

Sum of zeroes:0

We know that,

Sum of zeroes of a quadratic equation = -b/a = -(coefficient of x)/(coefficient of x^2)

Sum of zeroes = -(-(p+4))/1

0 = (p+4)

p+4=0

p = -4

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Answer 2

The value of p = - 4

Given :

• The quadratic equation x² - (p + 4)x + 5 = 0

• The sum of roots of the quadratic equation is 0

To find :

The value of p

Solution :

Step 1 of 2 :

Find sum of the roots of the equation

Here the given Quadratic equation is

x² - (p + 4)x + 5 = 0

Comparing with the general quadratic equation ax² + bx + c = 0 we get

a = 1 , b = - (p + 4) , c = 5

Sum of the roots = - b/a = (p + 4)

Step 2 of 2 :

Find the value of p

Here it is given that sum of roots of the quadratic equation is 0

By the given condition

p + 4 = 0

⇒ p = - 4

Hence the required value of p = - 4

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