If the sum of roots of the quadratic equation (k + 2)x2 + (7k + 3)x – 10 = 0 (k ≠ –2)is equal to the product of roots, then the value of k is
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Here is your answer,
Given ,
The sum of roots of the quadratic equation (k + 2)x2 + (7k + 3)x – 10 = 0 (k ≠ –2)is equal to the product of roots
Sum of zeroes = -b/a
= - ( 7k+3 ) / k+2
Product of zeroes = c/a
= -10/k+2
Sum of zeroes = Product of zeroes
-(7k+3) / k+2 = -10/k+2
-(7k+3) = -10
-7k + 3 = -10
-7k = -10 - 3
-13 = -7k
k = 13/7
Hope it helps you!
Here is your answer,
Given ,
The sum of roots of the quadratic equation (k + 2)x2 + (7k + 3)x – 10 = 0 (k ≠ –2)is equal to the product of roots
Sum of zeroes = -b/a
= - ( 7k+3 ) / k+2
Product of zeroes = c/a
= -10/k+2
Sum of zeroes = Product of zeroes
-(7k+3) / k+2 = -10/k+2
-(7k+3) = -10
-7k + 3 = -10
-7k = -10 - 3
-13 = -7k
k = 13/7
Hope it helps you!
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