If the sum of seven exterior angles is 200 degrees, find the sum of the eight interior angles not adjacent to these exterior angles.
Answers
Step-by-step explanation:
exterior angle + interior adjacent angle = 180° [Linear pair] Applying relation for polygon having n sides Sum of all exterior angles + Sum of all interior angles = nx 180° Sum of all exterior angles = nx 180° - Sum of all interior angles =n× 180° - (n-2) × 180° [Sum of interior angles is = (n - 2) x 180°] ning A
nx 180° - nx 180° +2 x 180° = 180°n - 180°n + 360°
= 360°
Sum of four exterior angles is 360°
15. In Figure, the bisectors of ZA and ZB meet at a point P. If ZC =100° and ZD= 50°, find the measure of ZAPB. D
50°
100⁰
A
B
Solution:
We know that Sum of angles of a quadrilateral is = 360°
In the quadrilateral ABCD
Given, ZC 100° and ZD= 50° ZA + 2B + ZC + ZD=360
Answer:
Wjere is the fig but acc to que the ans should be ,---360deg