Math, asked by MohdShahnawaz9427, 19 days ago

If the sum of seven exterior angles is 200 degrees, find the sum of the eight interior angles not adjacent to these exterior angles.

Answers

Answered by pranavraghav
0

Step-by-step explanation:

exterior angle + interior adjacent angle = 180° [Linear pair] Applying relation for polygon having n sides Sum of all exterior angles + Sum of all interior angles = nx 180° Sum of all exterior angles = nx 180° - Sum of all interior angles =n× 180° - (n-2) × 180° [Sum of interior angles is = (n - 2) x 180°] ning A

nx 180° - nx 180° +2 x 180° = 180°n - 180°n + 360°

= 360°

Sum of four exterior angles is 360°

15. In Figure, the bisectors of ZA and ZB meet at a point P. If ZC =100° and ZD= 50°, find the measure of ZAPB. D

50°

100⁰

A

B

Solution:

We know that Sum of angles of a quadrilateral is = 360°

In the quadrilateral ABCD

Given, ZC 100° and ZD= 50° ZA + 2B + ZC + ZD=360

Answered by ag8717842
0

Answer:

Wjere is the fig but acc to que the ans should be ,---360deg

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