if the sum of seven terms of an ap is 49 and that of its first 17 term is 289 find the sum of first n terms of AP
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s7=49
=>7/2(2a+(7-1)d)=49=>7/2(2a+6d)=49=>14a+42d=98=>a+3d=7......(1)
s17=289
Similarly by applying above formula
a+8d=27.............(2)
Subtracting 1 and 2 we get,
d=4
substituting this value of d in 2 we get
a=-5
From these value of a and d we get
-2n-7n to the power2
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