If the sum of square of the zeroes of the polynomial x^2-8x+k is 40. Fjnd k
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let the roots be a and b
a^2 + b^2 = 40
a + b = 8
(a + b)^2 - 2k = 40
64-40=2K
K=24/2 = 12
a^2 + b^2 = 40
a + b = 8
(a + b)^2 - 2k = 40
64-40=2K
K=24/2 = 12
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