Question

If the sum of squares of 10 terms is 38500, variance is 825, then coefficient of standard deviation is
a) 0.24 b) 0.25 c) 0.42 d) 0.52

Answer 1

Step-by-step explanation:

b 0.25 hope this helps you. THANKYOU mark me the brainist

Answer 2

Given :-

• Total terms = 10 .
• sum of square of all terms = 38500
• Variance = 825 .

To Find :-

• Coefficient of standard deviation ?

Formula used :-

• variance = (sum of Square of all terms / No. of terms) - (Mean)²
• Standard deviation is square root of the variance.
• Coefficient of standard deviation = (standard deviation / Mean) * 100%.

Solution :-

Putting all values in variance formula we get,

→ 825 = (38500/10) - (Mean)²

→ (Mean)² = 3850 - 825

→ (Mean)² = 3025

Square - root both sides,

→ Mean = 55.

Now,

→ Standard deviation = √(variance)

→ SD = √825

→ SD ≈ 28.72

Therefore,

→ Coefficient of standard deviation = (standard deviation / Mean) * 100%.

→ Coefficient of standard deviation = (28.72 / 55) * 100%

→ Coefficient of standard deviation = (28.72 * 100) / (55 * 100)

→ Coefficient of standard deviation = (2872 / 5500)

→ Coefficient of standard deviation = 0.52 (d) (Ans.)

Therefore, coefficient of standard deviation is 0.52 .