Question

If the sum of squares of two consecutive odd natural numbers is 290.What are the numbers?​

Answer 1

Answer:

11, 13

Step-by-step explanation:

1st odd no. 2x-1

2nd odd no. 2(x+1) - 1

(2x-1)² + [2(x+1)-1]² = 290

(4x² - 4x + 1) + (4x² + 4x + 1) = 290

8x² + 2 = 290

8x² = 288

x = 6, -6

1st odd no. 2x-1 = 2(6) - 1

                          = 11

2nd odd no. 2(x+1) - 1 = 2(6+1) - 1

                          = 13

Hope this Helps.