Question

If the sum of squares of zeros of the polynomial 6x²+x+k is 25/36 find the value of k.​

Answer 1

Your answer is -2.

hope it helps you

Answer 2

Answer:

K= 2

Step-by-step explanation:

(A+B) ^2  = 25/36

   THE POLYNOMIAL IS -------6x^2 + x + k

A+B = -b/a = -1/ 6            A×B= c/a = k/6

(A+B )^2 =  $A^{2} + B ^{2} + 2AB$

               $\frac{25}{36} = \frac{-1}{6} ^{2} + 2 (\frac{k}{6} )$

which in the last becomes ,

2=k

thank you