Question

if
the sum of squares of zeros of the polynominal 6x^2+x+k is 25/36
find the value of K.​

Answer 1

Answer:

Step-by-step explanation:

We know that polynomial form of zeroes is

X^2+(a+b)+ ab where a and b are zeroes

Hence your question is x^2+x/6+k/6

Here (a+b)²=(1/6)²=1/36

a²+ b²=25/36 given in question

(a+b)²=a²+b²+2ab

1/36=25/36+2k/6

24/36=k/3

2/3=k/3

Therefore k=2