Math, asked by bhoomi2177, 1 year ago

if the sum of the 3rd and 4th terms of a GP.be 60 and that of the 8th and
7th terms bo 480, find the 10th term of the G.P​

Answers

Answered by Anonymous
10

Answer:

10 term of the GP is 2560

Attachments:
Answered by amitnrw
3

10th term of GP = 2560 if the sum of the 3rd and 4th terms of a GP.be 60

Step-by-step explanation:

Correction : sum of 6th & 7th term = 480  

Let say first term = a

Common ratio = r

3rd term = ar²

4th term = ar³

ar² + ar³ = 60

=> ar²(1 + r) = 60

6th term = ar⁵

7th term = ar⁶

ar⁵ + ar⁶ = 480

=> ar⁵(1 +r) = 480

=> r³ ar²(1 + r)  = 480

=> r³ * 60 = 480

=>  r³ = 8

=> r = 2

ar²(1 + r) = 60

=> a*2²(1 + 2) = 60

=> a = 5

GP

5  , 10  , 20  ,  40  , 80 , 160 , 320  , 640  , 1280 , 2560 .......

10th term = ar⁹ = 5 * 2⁹  = 2560

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