if the sum of the 3rd and 4th terms of a GP.be 60 and that of the 8th and
7th terms bo 480, find the 10th term of the G.P
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Answer:
10 term of the GP is 2560
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10th term of GP = 2560 if the sum of the 3rd and 4th terms of a GP.be 60
Step-by-step explanation:
Correction : sum of 6th & 7th term = 480
Let say first term = a
Common ratio = r
3rd term = ar²
4th term = ar³
ar² + ar³ = 60
=> ar²(1 + r) = 60
6th term = ar⁵
7th term = ar⁶
ar⁵ + ar⁶ = 480
=> ar⁵(1 +r) = 480
=> r³ ar²(1 + r) = 480
=> r³ * 60 = 480
=> r³ = 8
=> r = 2
ar²(1 + r) = 60
=> a*2²(1 + 2) = 60
=> a = 5
GP
5 , 10 , 20 , 40 , 80 , 160 , 320 , 640 , 1280 , 2560 .......
10th term = ar⁹ = 5 * 2⁹ = 2560
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