Question

if the sum of the ages of a father and his son in years is 65 and twice the difference of their ages in years is 50 , then age of the father is:​

Answer 1

Answer:

45

Step-by-step explanation:

Let the age of father be a

and age of son be b

sum of age of father and son = 64 years

a + b = 65 ------ equation 1

twice the difference of age = 50 years

2 ( a - b ) = 50

a - b = 50 / 2 = 25 ------ equation 2

solving 1 and 2 equation for a and b

a + b = 65

a - b = 25

-----------------

2a = 90

a = 90 / 2 = 45

a + b = 65

45 + b = 65

b = 65 - 45 = 20

age of father , a = 45