Question

if the sum of the ages of two brothers is 35.One brother is two third of the other brother's age.Find their ages

Answer 1

Answer:

$\sf \green {\therefore \: First \: brother's \: age = 14 \: years}$

$\sf \green {Second \: brother's \: age = 21 \: years}$

Step-by-step explanation:

Let the second brother's age be 'x'

$\sf \frac{2}{3} x + x = 35$

$\sf \frac{2x}{3} + \frac{3x}{3} = 35$

$\sf \frac{5x}{3} = 35$

$\sf 5x = 35 \times 3$

$\sf5x = 105$

$\sf x = \frac{105}{5} = 21$

Now, lets find the first brother's age

$\sf \frac{2}{ \cancel3} \times { \cancel{21}}^{7} = 2 \times 7 = 14$

Answer 2

Answer:

One 21 and the other is 14

Step-by-step explanation:

$B_{1}$ is Brother 1

$B_{2}$ is Brother 2

Given:

• $B_{1} + B_{2} = 35$
• $B_{2}=\frac{2}{3}B_{1}$

Working out:

Any 2 numbers that add to 35 whilst one number is two-thirds of the other.

You can use trial and error to get your answer.

$\frac{2}{3}$ × 21 = 14 ✅

So the 2 ages are 14 and 21