If the sum of the ages of two sisters 3 years ago was 36 years then their sum of the ages after 4 years will be
(a) 30
(b) 40
(c) 50
(d) 54
Answers
Answered by
1
Step-by-step explanation:
present age of sisters =x,y
then 3years ago sum of their ages
x-3+y-3=36
x+y=42
sum of ages after 4years =x+4+y+4=x+y+8=50
Answered by
1
Answer:
46
Step-by-step explanation:
Let the present ages of both the sisters be X and Y.
therefore, their age before 3 years will be (X - 3) years and (y - 3) years.
So by given condition we get,
(X - 3) + (y - 3) = 36
x - 3 + y - 3 = 36
x + y - 6 = 36
So, x + y = 42
that means, the sum of present ages will be 42
Now, their ages 4 years hence will be (x +4) years and (y + 4) years. Also sum of those ages will be (42. + 4) i.e. 46
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