If the sum of the areas of two squares is 15425 m square and their if the perimeter difference is 60 m then find the side of the
square
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pushpajoshi0222
Secondary SchoolMath 5+3 pts
Sum of the areas of two squares is 468 m square if the difference of their perimeter is 24 m find the sides of the two square
Report by DivyaSoni 04.01.2018
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danoct2004
Danoct2004 Expert
Let the side of the larger square be x.
Let the side of the smaller square be y.
According to the question, x2 + y2 = 468 --------- (1)
Perimeters of the squares = 4x and 4y.
⇒ 4x - 4y = 24
⇒ x– y = 6
⇒ x= 6 + y
x2 + y2 = 468
Substituting the value of x in equation (1)
⇒ (6+y)2 + y2 = 468
⇒ 2y2 + 12y + 36 = 468
⇒ y2 + 6y + 18 = 234
⇒ y2 + 6y - 216 = 0
⇒ (y – 12)(y + 18) = 0
⇒ y = 12 or -18
Since y denotes a length, it cannot be negative.
∴ y = 12
⇒ x = (12 + 6) = 18 m
∴ Sides of the squares are 18 m and 12 m.
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