Question

If the sum of the co-efficients in the expansion of (ax²+2ax+1)⁵¹ vanishes, then the value of a is​

Answer 1

Answer:

Put x=1 in (a

2

x

2

−2ax+1)

51

,

(a

2

(1)

2

−2a(1)+1)

51

=(a

2

−2a+1)

51

Since the sum of the coefficients vanishes, then,

(a

2

−2a+1)

51

=0

This is only possible if a=1, because,

(1

2

−2(1)+1)=1−2+1

=0

Therefore, the value of a is 1.

Step-by-step explanation:

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