If the sum of the distance of a moving point from 2 perp. lines in a plane is always 1 then its locus is?
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Hey.
Here is the answer.
Let the perpendiculars lines be the x – axis and y – axis. The sum of the distances from the the point P (x, y) is 1. ie.
|x| + |y| = 1 – this is the locus of the point P which would be the rhombus whose sides are
x + y = 1; –x + y = 1; x – y = 1; –x – y = 1
If the perpendicular lines are other than co-ordinate axes, then we can get the same solution by using the transformation of the axes concept.
So, rhombus or can say square is the answer .
Thanks.
Here is the answer.
Let the perpendiculars lines be the x – axis and y – axis. The sum of the distances from the the point P (x, y) is 1. ie.
|x| + |y| = 1 – this is the locus of the point P which would be the rhombus whose sides are
x + y = 1; –x + y = 1; x – y = 1; –x – y = 1
If the perpendicular lines are other than co-ordinate axes, then we can get the same solution by using the transformation of the axes concept.
So, rhombus or can say square is the answer .
Thanks.
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