Question

If the sum of the equation 3x-(3k-2)x-(k-6) is equal to the product of its roots find k

Answer 1

Answer:

$3 {x}^{2} - (3k - 2)x - (k - 6) = 0 \\ \alpha + \beta = \alpha \beta \\ \frac{3k - 2}{3} = \frac{ - (k - 6)}{3} \\ 3k - 2 = - k + 6 \\ k = 2$