Question

If the sum of the first 12 terms of an a.p is 468 and its common difference is 6. find the 10th term.

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

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• Sum of first 12 terms of an AP is 468.

• Common difference is 6

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$\red{\underline \bold{To \: Find:}}$

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• The 10th term.

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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$\underline{\bold{\texttt{We know that :}}}$

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$\purple\longrightarrow$ $\sf S_n = \dfrac { n } { 2 } (2a + (n - 1)d)$

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• $\rm S_n \: = \: sum \: of \: n \: terms.$

• $\rm a \: = \: First \: term \: of \: the AP$

• $\rm d \: = \: common \: difference \: of \: the \: AP$

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$\sf \longmapsto 468 = \dfrac { 12} { 2 } (2a + (12 - 1)6)$

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$\sf \longmapsto 468 = 6(2a + 66)$

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$\sf \longmapsto 78 = 2a + 66$

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$\sf \longmapsto 2a = 12$

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$\sf \longmapsto a = \dfrac { 12 } { 2 }$

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$\bf\longmapsto a = 6$

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Hence first term is 6

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$\underline{\bold{\texttt{For 10th term:}}}$

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$\purple\longrightarrow$ $\sf a_n = a + (n - 1)d$

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$\sf \longmapsto 10th \: term \: = 6 + (10 - 1)6$

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$\sf \longmapsto 10th \: term \: = 6 + 54$

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$\bf\longmapsto 10th \: term \: = 60$

$\rule{200}5$

Answer 2

Answer:

the answer is

Step-by-step explanation:

60

pls make it brainlest answer