If the sum of the first 14 terms of an A.P is 1050 and it's first term is 10, find the 20th term.
Answers
Answered by
34
Hey Mate!
Given,
Sum of first 14 terms = 1050
S14 = n/2 ( 2a + ( n - 1) d
S14 = 14/2 ( 2 (10) + 13d)
1050 = 7 ( 20 + 13d)
1050/7 = 20 + 13d
150 = 20 + 13d
150 - 20 = 13d
130 = 13d
d = 130/13
d = 10
20th term = a + 19d
= 10 + 190
= 200
HOPE THIS HELPS U...
Given,
Sum of first 14 terms = 1050
S14 = n/2 ( 2a + ( n - 1) d
S14 = 14/2 ( 2 (10) + 13d)
1050 = 7 ( 20 + 13d)
1050/7 = 20 + 13d
150 = 20 + 13d
150 - 20 = 13d
130 = 13d
d = 130/13
d = 10
20th term = a + 19d
= 10 + 190
= 200
HOPE THIS HELPS U...
Answered by
16
Solution:-
Given:-
S14 = 14/2 [ 2a + ( 14 - 1)d ] = 1050.
a = First Term = 10.
To Find :-
a20 = ?
Find:-
=) sn = n/2 [ 2a + ( n-1)d ]
=) s14 = 14/2 [ 2(10) + ( 14 - 1)d ]
=) 1050 = 7 [ 20 + 13d ]
=) 1050/7 = 20 + 13d
=) 150 - 20 = 13d
=) d = 130/13
=) d = 10.
Now,
a20 = a + 19d
=) a20 = 10 + 19×10
=) a20 = 10 + 190
=) a20 = 200.
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