If the sum of the first 14 terms of an A.P. is 1050 and its first term is 10, then find the 21st
term of the A.P.
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Answer:
S14=1050 a=10 a21=?
Step-by-step explanation:
S14=14/2(2×10+13d)
1050=7(20+13d)
1050/7=20+13d
150-20=13d
d=130/13
d=10
a21=a+20d
a21=10+20×10
a21=10+200
a21=210.
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