If the sum of the first 3 terms of an AP is 20 and product of the First three terms is 150. Find the first term.
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The sum of the first 10 terms of the AP is - 150 and the sum of the first 20 terms is 0150–550 = -700.
S10 = (10/2)[2a+(10–1)d] = -150, or
-30 = 2a + 9d, or
2a = -30–9d …(1)
S20 = -700 = (20/2)[2a+(20–1)d], or
-70 = 2a + 19d, or
2a = -70–19d …(2)
Equate (1) and (2),
-30–9d = -70–19d, or
10d = -40, or
d = -4.
From (1), 2a = -30+36 = 6, or a = 3.
The first term of the AP = 3 and the common ratio = -4. Or the AP is 3, -1, -5, -9,…
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