if the sum of the first 7 term of an ap is 4g and that of 17 terms is 289 find the sum of the first n terms
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1
Answer:
n²
Step-by-step explanation:
I think the "4g" was meant to be "49". Let's proceed with that.
Let a be the first term and d the common difference.
The sum of the first n terms is na + [n(n-1)/2]d.
Putting n = 7:
7a + 7×3d = 49 => a + 3d = 7 ... (1)
Putting n = 17:
17a + 17×8d = 289 => a + 8d = 17 ... (2)
Subtracting equation (1) from equation (2):
5d = 10 => d = 2
Then from equaiton (1):
a = 7 - 3d = 7 - 6 = 1
Therefore, the sum of the first n terms is
na + [n(n-1)/2]d
= n + n(n-1)
= n + n² - n
= n²
bharath4255:
it 4g
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