If the sum of the first n term of an AP is 4n - n* What is the fifth term of AP?
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Answer:
A.P is 4n-n
Let n= 1,2,3,.......
So
n=1, S1=4n-n
= 4*1-1 = 3
n=2, S2= 4*2-2 =6
Then,
a1+a2 = 6
3+a2 = 6
a2 = 6-3
a2 = 3
d = a2-a1
= 3-3 = 0
a5 = a+4d
= 3 +4*0
a5 = 3
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