if the sum of the first n terms of an A.P. is 1/2 [3n square +7n], then find its n'th term. Also, write its 20th term.
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Answer:
Its nth term will be 3n+2
Step-by-step explanation:
Sn=½(3n² +7n)
Sn-1=½{3(n-1)²+7(n-1)}
=½{3(n²-1-2n)²+7n-1}
=½(3n²-3-6n+7n-1)
=½(3n²+n-4)
Tn=(Sn-Sn-1)
=½(3n²+7n)-½(3n²+n-4)
=½(6n+4)
=(3n+2)
Its nth term = (3n+2)
Its 20th term=(3n+2)
=(3×20+2)
=62
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