If the sum of the first n terms of an A.P. is 4n – n², which is the first term? What is the sum of first two terms? What is the second term? Similarly, find the third, the tenth and the nth terms.
Answers
Given the sum of n terms of an A.P -
Sn = 4n -n²
The first term of the A.P = S1 = 4-1 = 3 = a
=> a = 3
The sum of the first terms of the A.P = S2
= 4
=> a + a + d = 4
=> 2a + d = 4
=> d = -2
The common difference of the arithmetic progression is equal to -2.
The second term of the A.P = a + d = 1
The third term of the A.P = a + 2d = -1
The tenth term of the A.P = a + 9d = -15
The nth term of the given A.P = 3 + (n-1)×-2
( i ) The First term is 3
( i i ) The Second term is 4
( i i i )The sum of first two terms is 7
(i v ) The Third term is 5
( v ) The tenth term is 12
( v i ) The nth terms is (2 + n)
Step-by-step explanation:
Given as :
The sum of first n terms of an A.P = 4 n - n²
i.e = [ a + (n - 1) d ] = 4 n - n²
Or, = 4 n - n²
( i ) The First term
= 4 × 1 - 1²
Or, = 4 - 1 = 3
So, The first term = = 3
( i i ) The Second term
= 4 × 2 - 2²
Or, = 8 - 4 = 4
So, The second term = = 4
Now,
( i i i ) The sum of first two terms
+
Or, + = 3 + 4 = 7
∴ sum of first two terms = 7
Again
the first term = = a = 3
common difference = d = - = 4 - 3
i.e d = 1
(i v ) The Third term
= a + (n - 1) d
i.e = 3 + (3 - 1) 1
or, = 3 + 2 = 5
So, The third term = 5
( v ) The tenth term
= a + (n - 1) d
i.e = 3 + (10 - 1) 1
or, = 3 + 9 = 12
So, The tenth term = 12
( v i ) The nth terms
∵ = 3 + (n - 1) 1
or, = 3 + n - 1
∴ = 2 + n
So, The nth term = 2 + n
Hence,
( i ) The First term is 3
( i i ) The Second term is 4
( i i i )The sum of first two terms is 7
(i v ) The Third term is 5
( v ) The tenth term is 12
( v i ) The nth terms is (2 + n) Answer