Math, asked by himanahu466, 9 months ago

If the sum of the first n terms of an A.P. is 4n – n², which is the first term? What is the sum of first two terms? What is the second term? Similarly, find the third, the tenth and the nth terms.

Answers

Answered by ParvezShere
10

Given the sum of n terms of an A.P -

Sn = 4n -n²

The first term of the A.P = S1 = 4-1 = 3 = a

=> a = 3

The sum of the first terms of the A.P = S2

= 4

=> a + a + d = 4

=> 2a + d = 4

=> d = -2

The common difference of the arithmetic progression is equal to -2.

The second term of the A.P = a + d = 1

The third term of the A.P = a + 2d = -1

The tenth term of the A.P = a + 9d = -15

The nth term of the given A.P = 3 + (n-1)×-2

Answered by sanjeevk28012
2

( i ) The First term is 3

( i i ) The Second term is 4

( i i i )The sum of first two terms is 7

(i v ) The Third term is 5

( v ) The tenth term is 12

( v i ) The nth terms is (2 + n)

Step-by-step explanation:

Given as :

The sum of first n terms of an A.P = 4 n - n²

i.e   S_n  = \dfrac{n}{2} [ a + (n - 1) d ]  = 4 n - n²

Or, S_n  =  4 n - n²

( i ) The First term

t_1 = 4 × 1 - 1²

Or,   t_1 = 4 - 1 = 3

So, The first term = t_1 = 3

( i i ) The Second term

 t_2 = 4 × 2 - 2²

Or,       t_2 = 8 - 4 = 4

So, The second term = t_2 = 4

Now,

( i i i ) The sum of first two terms

t_1  +   t_2

Or,  t_1  +   t_2  = 3 + 4  = 7

sum of first two terms = 7

Again

the first term = t_1 = a = 3

common difference = d = t_2  - t_1  =  4 - 3

i.e    d = 1

(i v ) The Third term

t_3 = a + (n - 1) d

i.e  t_3 = 3 + (3 - 1) 1

or,  t_3 = 3 + 2 = 5

So, The third term = 5

( v ) The tenth term

t_1_0 = a + (n - 1) d

i.e  t_1_0 = 3 + (10 - 1) 1

or,  t_1_0 = 3 + 9 = 12

So, The tenth term = 12

( v i ) The nth terms

t_n  = 3 + (n - 1) 1

or, t_n = 3 + n - 1

∴   t_n = 2 + n

So, The nth term = 2 + n

Hence,

( i ) The First term is 3

( i i ) The Second term is 4

( i i i )The sum of first two terms is 7

(i v ) The Third term is 5

( v ) The tenth term is 12

( v i ) The nth terms is (2 + n)              Answer

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