Question

If the sum of the first n terms of an A.P. is 4n − , what is the common
difference?

Answer 1

Step-by-step explanation:

Sum of n terms =S

n

=2n+3n

2

S

1

=2(1)+3(1)

2

=5

Sum of 1st term is same as first term so a

1

=a=5

S

2

=2(2)+3(2)

2

=4+12=16

S

2

=a

1

+a

2

16=5+a

2

⇒a

2

=11

Common difference d=a

2

−a

1

=11−5=6

Answer 2

Answer:

11-5=6

Step-by-step explanation:

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