if the sum of the first n terms of an A.P. is given by 4n-n2, find its 10 terms
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Answer:
Ap = 4n-n2
find = 10 term
hence ap = 2 ,4,6,8,10,12..........
so a=2 , d = 4-2 = 2
n = 10
AN th = a + (n-1) d
= 2 + (10-1)2
=2+18
= 20 answer
Step-by-step explanation:
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