If the sum of the first n terms of an ap is 3n^2-2n find the ap and find its 19th
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Tanusheoran:
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we have to find the ap and its 19th term
ATQ
Sum = n/2 [2a + (n-1)d]
3n^2 - 2n = n/2 [ 2a + (n-1) d]
6n - 4 = 2a + (n-1)d
so ,
The nth term = 2a + (n-1)d = 6n - 4
Thus 19th term
A(19) = 6*19 - 4
=) 114-4 = 110
Hence the 19th term is 110
hop it helps you
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