if the sum of the first n terms of an ap is 4n-nsquare, find the 10th term
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sadiya12mi47:
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Answered by
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Answer:
the 10th term is 76
Step-by-step explanation:
let the 10th term of the AP be y
Now ,
summation upto 10tg term of the AP,
4×(10)^2 = 10/2{4(1)^2+ y}
400 = 5 (4 + y )
80 = 4 + y
y = 76
hence the 10th term of the AP is 76.
my hope this may help you
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