If the sum of the first n terms of an ap is given by sn=3n2-4n
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Given Sn = 3n^2 -4n
Sn = Sum of n numbers
n can be 1,2,3,4,.....
Nth term of an A.P = a+(n-1)d
First term = 3(1)^2 - 4(1) = 3-4 = -1
Sum of 1st and 2nd term = 3(2)^2 -4(2)
= 3(4) - 8
= 12-8
= 4
Second term = Sum of 1st and 2nd term - First term
=4-(-1) = 5
Difference between 1st and 2nd term = 5-4= 1
A.P = 4,5,6,.....
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