Question

if the sum of the first n terms of an AP is n(n+10) then find the first term and common difference​

Answer 1

*ANSWER*

S(n)= n(n+10)

putting n=1

S(1) = 1(1+10)

= 11

Therefore,

1st term 'a' = 11

putting n=2

S(2) = 2(2+10)

= 24

sum of 1st and the 2nd term is 24

Therefore 2nd term = 24-11

= 13

Therefore common difference 'd' = 13-11

= 2

so the 1st term 'a' = 11

and common difference 'd' = 2

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