If the sum of the first n terms of an arithmetic progression is given by the equation
15n + 3n2, then what is the 18th element of this AP?
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Answered by
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Answer:
3n2+2n
Taking n=1, we get
S1=3(1)2+2(1)
⇒S1=3+2
⇒S1=5
⇒a1=5
Taking n=2, we get
S2=3(2)2+2(2)
⇒S2=12+4
⇒S2=16
∴a2=S2−S1=16−5=11
Taking n=3, we get
S3=3(3)2+2(3)
⇒S3=27+6
⇒S3=33
∴a3=S3−S2=33−16=17
So, a=5,
d=
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