if the sum of the first n terms of the AP sn = n^2 + 3n. then the third term of the AP is.
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if sn= n^2 +3n
third term= (sum of first third terms)-(sum of first
two terms)
third term= [(3)^(2)+ 3 (3)] - [(2)^(2)+3 (2)]
= [9+9] - [4+6]
=18-10
=8
therefore, third term=8
hope it helps...
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