Math, asked by Sahil6690, 11 months ago

If the sum of the first n terms of the series \sqrt{3}+\sqrt{75}+\sqrt{243}+\sqrt{507}+......\ is\ 435\sqrt{3}, then n equals:
(a) 18
(b) 15
(c) 13
(d) 29

Answers

Answered by rahman786khalilu
3

Hope it helps! mark as brainliest

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