Math, asked by Sahil6690, 1 year ago

If the sum of the first n terms of the series $\sqrt{3}+\sqrt{75}+\sqrt{243}+\sqrt{507}+......\ is\ 435\sqrt{3}$ , then n equals:
(a) 18
(b) 15
(c) 13
(d) 29

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Answered by rahman786khalilu

Hope it helps! mark as brainliest

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